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PHP Code debug

I have setup a staging directory with a copy of the code that I am running.

When a user hits the site there is a csv keyword that is in the url, example ([url removed, login to view])

this keyword is passed to the [url removed, login to view] page which querys a mysql table against that csvkeyword.

Once the query is compleated the [url removed, login to view] page reads the content template page that is specified on line 6 of [url removed, login to view] and will replace all the varible values in that page with the data it pulled from the mysql table.

My problem is this. if you look at the content page (/var/www/staging/[url removed, login to view]) i have a colum of junk in the right hand side, I wrote a MSSQL query (/var/www/staging/[url removed, login to view]) that issues a query against a stored precedure that I want to display in that right hand colum. When I drop this code into the content template page ([url removed, login to view]) that is read by the [url removed, login to view] page it breaks everything.

I have a feeling it is related to the loop in teh MSSQL query and the loop that runs on the [url removed, login to view] page.

Færdigheder: PHP, Software Arkitektur

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Om arbejdsgiveren:
( 8 bedømmelser ) Anthem, United States

Projekt-ID: #960859

Tildelt til:

DrTech76

All right then.

$30 USD in 0 dage
(307 bedømmelser)
6.7

4 freelancere byder i gennemsnit $38 for dette job

expertspk

hi, i can do this . let's start

$30 USD på 1 dag
(109 bedømmelser)
6.6
junaidart

Get it fixed in less than one hour.

$40 USD in 0 dage
(94 bedømmelser)
6.1
priboy

Please check PMB

$50 USD på 1 dag
(9 bedømmelser)
5.6
nicewebtech

php expert here lets start.

$30 USD på 1 dag
(9 bedømmelser)
3.1