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Modifying existing Web Page based on Php / Ajax

Modifying existing Web Page based on Php / Ajax / Java.

Modification of a webpage which is used as webinterface for a dardware

we have developed.

Færdigheder: Android, Mobile App Development

Se mere: php ajax, modifying, web page mobile, existing web, modification android, java web page, android webpage, php ajax webpage, mobile web page php, ajax android php, php java android, ajax mobile, php mobile ajax, android phone modification, mobile web page, modification ajax php, android web page, mobile ajax, php ajax pending, android modification, android ajax php, php ajax page, ajax web phone, webpage android, android ajax

Om arbejdsgiveren:
( 0 bedømmelser ) Cologne, Germany

Projekt-ID: #6023386

Tildelt til:

ambar

A proposal has not yet been provided

$160 USD in 5 dage
(18 bedømmelser)
7.0

4 freelancere byder i gennemsnit $185 for dette job

babysoftS

Hi, I am expert web developer with expertise in PHP5, MySQl, AJAX etc. Can you provide the details of the modification required? I can modify the existing web page as required. thanks Vibhor

$189 USD in 3 dage
(21 bedømmelser)
6.4
websofttechno

A proposal has not yet been provided

$147 USD in 3 dage
(5 bedømmelser)
3.0
xcodejok

please check our company freelancer profile [url removed, login to view] we already developed this type of project so we can take your project. why you hire us ? have 5*** with 100% complete rate with we Mere

$115 USD in 3 dage
(8 bedømmelser)
2.9
pointlogic

Hello..I have an experience of more than 4 years in web development and maintenance. I have in-depth knowledge of php, mysql, jquery, paypal integrations, API's, css, html, html5. Our team is experienced, creative & Mere

$263 USD in 3 dage
(1 bedømmelse)
2.0
MakhijaRavi

Hello Sir/Madam, I have just seen your Job posting and upon reading thoroughly, I felt strongly that I would be the most qualified contractor for this project. My skills include Web Design, Graphic Design, and Web Deve Mere

$126 USD på 1 dag
(0 bedømmelser)
0.0