NodeJS Body Paser Filter Json responce

Looking for code that can filter an json http post responce of say a requested user 33221 then parse that against a list array of static names ie "33221" , "99121" and if it is not in this static array respond with http 403 responce of " Access Not Allowed."

Evner: Javascript, node.js

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Om arbejdsgiveren:
( 2 bedømmelser ) Melbourne, United States

Projekt ID: #17826422

Tildelt til:


Hello, I can help you with this matter quickly. All i need is the format of the posted data and the endpoint where that data is processed. I hope we can collaborate together. Regards

$55 USD på 1 dag
(47 bedømmelser)

7 freelancere byder i gennemsnit $37 på dette job


Dear employer! Thank you for your opportunity! [login to view URL] is my portfolio site. [login to view URL] is my github repositories. Here is a MEAN / MERN stack developer. I Flere

$111 USD på 1 dag
(13 bedømmelser)

Hello, I’d really like to work with you on this one if possible! I've been a web developer for 10+ years however, I am new to Freelancer.co.uk and looking to get a few clients that I can build upon. You’ll get Flere

$10 USD på 1 dag
(1 bedømmelse)

We can do this project for you efficiently, quickly and economically. Please contact us if you have any questions. We hope to be elected. Greetings

$10 USD på 1 dag
(0 bedømmelser)

Hi, I've been working as a professional NodeJS developer from past 4 years. i can do the work in appropriate time and budget. We can discuss more on the project if you are interested. Looking forward to work with you. Flere

$20 USD på 1 dag
(0 bedømmelser)

Bid based on one section of code to check database for user and throw error 403 if not found. If user is found I can render whatever you want to for that user.

$35 USD in 3 dage
(0 bedømmelser)

Hey! Im new to freelancer posting bid as a professional to get my first review. I need to offer myself as a contender for this employment since I have the required aptitudes that you are searching for. I have been wor Flere

$15 USD på 1 dag
(0 bedømmelser)