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[C] Change the architecture of a simple C program

Hello everyone,

I will need someone to complete a very simple change on 2 existing C files. I will need you to change the following to my files:

1. Different variable and function names. Different file names

2. Different input file format and data

3. Comments per line

4. Different blank spaces

5. Different architecture on the *variables and functions

This will be needed for today next 3-4 hours and i will pay it today

Budget: $15 USD

Evner: C++ Programmering, C programmering, C# Programmering, Software Arkitektur, PHP

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Om arbejdsgiveren:
( 209 bedømmelser ) Thessaloniki, Kalamaria, Greece

Projekt ID: #32220010

7 freelancere byder i gennemsnit $16 timen for dette job

(182 bedømmelser)
6.5
elhosayny

Hi, I can modify the c files according to your needs, please send a message to dicusss details. Best regards.

$30 USD på 1 dag
(13 bedømmelser)
3.9
dmitriysenkojob

Hello! Ready to help you with your project. Let's discuss details in the chat. I am experienced C# developer, so don't worry about quality and timing.

$15 USD på 1 dag
(12 bedømmelser)
3.6
akavya0306

Hello I am a experienced programmer. I'm very interested in your job, I'll do it as fast as I can. I've read requirements and I'm ready.

$10 USD på 1 dag
(0 bedømmelser)
0.0
swaggerino

Hi! i am an experienced software developer. i could deliver what you need in hours! i did a lot of C, C++ and C# programming in past. let me know if you are interested ?

$20 USD på 1 dag
(0 bedømmelser)
0.0
ozdemirkulaoglu

Hello, I am experienced software developer. My local environment is ready to modify your 2 existing C file in 2 hours mostly. I am new in here. So, I will be quickly complete your project with best performance. If y Flere

$10 USD på 1 dag
(0 bedømmelser)
0.0
micro3d

Hello. This should be a simple task assuming that the files are not excessively long. I can rewrite those C files for you as required. What is the target system where these files are to be compiled?

$15 USD på 1 dag
(0 bedømmelser)
0.0