Binary Tree ADT implementation

  • Status: Closed
  • Præmier: $15
  • Modtagne indlæg: 1

Konkurrence Instruktioner

Build an implementation of a binary-tree ADT and Use it to evaluate an arithmetic expression which (for the sake of simplicity) includes only binary operations. JAVA is to be used as a programming language.

Problem Description
1. The purpose of the exercise is to practice building and traversing an expression tree; so I want you to build a tree to hold the expression and to evaluate the expression by traversing the tree. If you have another idea about how to evaluate the expression without building the expression tree, I encourage you to reconsider.

2. Please use the following syntax for the arithmetic expressions that I want you to process:
<expression> ::= <term> | <term> + <expression> | <term> - <expression>
<term> ::= <factor> | <factor> * <term> | <factor> / <term>
<factor> ::= <constant> | ( <expression> )
<constant> ::= 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
You can make it slightly more complex by allowing greater integers than 9 but you can let your constants range from 0 to 9 only.

3. Make sure you understand how this syntax defines operator precedence and associativity rule. Operator precedence: 3*5+4 is interpreted as (3*5)+4 rather than 3*(5+4). associativity rule: 3-5-4 is interpreted as 3-(5-4) rather than (3-5)-4.

4. Supply a two pager technical description of the program you wrote (this can be kept for later, if you win the contest)

5. Please write the code well commented

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Offentlig Præciserings Opslagstavle

  • abdou93
    • 2 år siden

    i can do it with stacks only without using trees

    • 2 år siden
    1. abdou93
      • 2 år siden

      i know that but stacks more simple for that task

      • 2 år siden
    2. Gangwani
      • 2 år siden

      the idea was used to show an implementation of tree and not to chose the simpler one between tree and stacks

      • 2 år siden
  • zain010
    • 2 år siden

    #guaranteed please

    • 2 år siden
    1. Gangwani
      • 2 år siden

      Well you are the only one as of now, so chances for winning are high!

      • 2 år siden

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